(x+1)(2x^2-9x-4)=0

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Solution for (x+1)(2x^2-9x-4)=0 equation: 


Simplifying
(x + 1)(2x2 + -9x + -4) = 0

Reorder the terms:
(1 + x)(2x2 + -9x + -4) = 0

Reorder the terms:
(1 + x)(-4 + -9x + 2x2) = 0

Multiply (1 + x) * (-4 + -9x + 2x2)
(1(-4 + -9x + 2x2) + x(-4 + -9x + 2x2)) = 0
((-4 * 1 + -9x * 1 + 2x2 * 1) + x(-4 + -9x + 2x2)) = 0
((-4 + -9x + 2x2) + x(-4 + -9x + 2x2)) = 0
(-4 + -9x + 2x2 + (-4 * x + -9x * x + 2x2 * x)) = 0
(-4 + -9x + 2x2 + (-4x + -9x2 + 2x3)) = 0

Reorder the terms:
(-4 + -9x + -4x + 2x2 + -9x2 + 2x3) = 0

Combine like terms: -9x + -4x = -13x
(-4 + -13x + 2x2 + -9x2 + 2x3) = 0

Combine like terms: 2x2 + -9x2 = -7x2
(-4 + -13x + -7x2 + 2x3) = 0

Solving
-4 + -13x + -7x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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